mirror of
https://gitlab.com/pulsechaincom/erigon-pulse.git
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330 lines
8.5 KiB
Go
330 lines
8.5 KiB
Go
// Copyright 2019 The go-ethereum Authors
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// This file is part of the go-ethereum library.
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//
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// The go-ethereum library is free software: you can redistribute it and/or modify
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// it under the terms of the GNU Lesser General Public License as published by
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// the Free Software Foundation, either version 3 of the License, or
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// (at your option) any later version.
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//
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// The go-ethereum library is distributed in the hope that it will be useful,
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// but WITHOUT ANY WARRANTY; without even the implied warranty of
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// MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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// GNU Lesser General Public License for more details.
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//
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// You should have received a copy of the GNU Lesser General Public License
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// along with the go-ethereum library. If not, see <http://www.gnu.org/licenses/>.
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package dnsdisc
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import (
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"context"
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"math/rand"
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"time"
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"github.com/ledgerwatch/erigon/common/mclock"
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"github.com/ledgerwatch/erigon/p2p/enode"
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)
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// This is the number of consecutive leaf requests that may fail before
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// we consider re-resolving the tree root.
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const rootRecheckFailCount = 5
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// clientTree is a full tree being synced.
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type clientTree struct {
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c *Client
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loc *linkEntry // link to this tree
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lastRootCheck mclock.AbsTime // last revalidation of root
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leafFailCount int
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rootFailCount int
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root *rootEntry
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enrs *subtreeSync
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links *subtreeSync
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lc *linkCache // tracks all links between all trees
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curLinks map[string]struct{} // links contained in this tree
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linkGCRoot string // root on which last link GC has run
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}
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func newClientTree(c *Client, lc *linkCache, loc *linkEntry) *clientTree {
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return &clientTree{c: c, lc: lc, loc: loc}
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}
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// syncAll retrieves all entries of the tree.
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func (ct *clientTree) syncAll(dest map[string]entry) error {
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if err := ct.updateRoot(context.Background()); err != nil {
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return err
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}
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if err := ct.links.resolveAll(dest); err != nil {
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return err
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}
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if err := ct.enrs.resolveAll(dest); err != nil {
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return err
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}
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return nil
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}
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// syncRandom retrieves a single entry of the tree. The Node return value
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// is non-nil if the entry was a node.
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func (ct *clientTree) syncRandom(ctx context.Context) (n *enode.Node, err error) {
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if ct.rootUpdateDue() {
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if err = ct.updateRoot(ctx); err != nil {
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return nil, err
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}
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}
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// Update fail counter for leaf request errors.
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defer func() {
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if err != nil {
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ct.leafFailCount++
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}
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}()
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// Link tree sync has priority, run it to completion before syncing ENRs.
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if !ct.links.done() {
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err := ct.syncNextLink(ctx)
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return nil, err
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}
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ct.gcLinks()
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// Sync next random entry in ENR tree. Once every node has been visited, we simply
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// start over. This is fine because entries are cached internally by the client LRU
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// also by DNS resolvers.
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if ct.enrs.done() {
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ct.enrs = newSubtreeSync(ct.c, ct.loc, ct.root.eroot, false)
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}
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return ct.syncNextRandomENR(ctx)
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}
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// canSyncRandom checks if any meaningful action can be performed by syncRandom.
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func (ct *clientTree) canSyncRandom() bool {
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// Note: the check for non-zero leaf count is very important here.
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// If we're done syncing all nodes, and no leaves were found, the tree
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// is empty and we can't use it for sync.
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return ct.rootUpdateDue() || !ct.links.done() || !ct.enrs.done() || ct.enrs.leaves != 0
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}
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// gcLinks removes outdated links from the global link cache. GC runs once
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// when the link sync finishes.
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func (ct *clientTree) gcLinks() {
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if !ct.links.done() || ct.root.lroot == ct.linkGCRoot {
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return
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}
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ct.lc.resetLinks(ct.loc.str, ct.curLinks)
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ct.linkGCRoot = ct.root.lroot
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}
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func (ct *clientTree) syncNextLink(ctx context.Context) error {
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hash := ct.links.missing[0]
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e, err := ct.links.resolveNext(ctx, hash)
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if err != nil {
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return err
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}
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ct.links.missing = ct.links.missing[1:]
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if dest, ok := e.(*linkEntry); ok {
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ct.lc.addLink(ct.loc.str, dest.str)
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ct.curLinks[dest.str] = struct{}{}
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}
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return nil
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}
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func (ct *clientTree) syncNextRandomENR(ctx context.Context) (*enode.Node, error) {
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index := rand.Intn(len(ct.enrs.missing)) //nolint:gosec
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hash := ct.enrs.missing[index]
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e, err := ct.enrs.resolveNext(ctx, hash)
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if err != nil {
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return nil, err
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}
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ct.enrs.missing = removeHash(ct.enrs.missing, index)
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if ee, ok := e.(*enrEntry); ok {
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return ee.node, nil
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}
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return nil, nil
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}
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func (ct *clientTree) String() string {
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return ct.loc.String()
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}
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// removeHash removes the element at index from h.
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func removeHash(h []string, index int) []string {
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if len(h) == 1 {
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return nil
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}
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last := len(h) - 1
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if index < last {
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h[index] = h[last]
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h[last] = ""
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}
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return h[:last]
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}
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// updateRoot ensures that the given tree has an up-to-date root.
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func (ct *clientTree) updateRoot(ctx context.Context) error {
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if !ct.slowdownRootUpdate(ctx) {
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return ctx.Err()
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}
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ct.lastRootCheck = ct.c.clock.Now()
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ctx, cancel := context.WithTimeout(ctx, ct.c.cfg.Timeout)
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defer cancel()
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root, err := ct.c.resolveRoot(ctx, ct.loc)
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if err != nil {
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ct.rootFailCount++
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return err
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}
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ct.root = &root
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ct.rootFailCount = 0
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ct.leafFailCount = 0
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// Invalidate subtrees if changed.
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if ct.links == nil || root.lroot != ct.links.root {
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ct.links = newSubtreeSync(ct.c, ct.loc, root.lroot, true)
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ct.curLinks = make(map[string]struct{})
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}
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if ct.enrs == nil || root.eroot != ct.enrs.root {
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ct.enrs = newSubtreeSync(ct.c, ct.loc, root.eroot, false)
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}
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return nil
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}
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// rootUpdateDue returns true when a root update is needed.
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func (ct *clientTree) rootUpdateDue() bool {
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tooManyFailures := ct.leafFailCount > rootRecheckFailCount
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scheduledCheck := ct.c.clock.Now() >= ct.nextScheduledRootCheck()
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return ct.root == nil || tooManyFailures || scheduledCheck
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}
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func (ct *clientTree) nextScheduledRootCheck() mclock.AbsTime {
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return ct.lastRootCheck.Add(ct.c.cfg.RecheckInterval)
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}
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// slowdownRootUpdate applies a delay to root resolution if is tried
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// too frequently. This avoids busy polling when the client is offline.
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// Returns true if the timeout passed, false if sync was canceled.
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func (ct *clientTree) slowdownRootUpdate(ctx context.Context) bool {
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var delay time.Duration
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switch {
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case ct.rootFailCount > 20:
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delay = 10 * time.Second
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case ct.rootFailCount > 5:
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delay = 5 * time.Second
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default:
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return true
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}
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timeout := ct.c.clock.NewTimer(delay)
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defer timeout.Stop()
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select {
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case <-timeout.C():
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return true
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case <-ctx.Done():
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return false
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}
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}
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// subtreeSync is the sync of an ENR or link subtree.
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type subtreeSync struct {
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c *Client
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loc *linkEntry
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root string
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missing []string // missing tree node hashes
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link bool // true if this sync is for the link tree
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leaves int // counter of synced leaves
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}
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func newSubtreeSync(c *Client, loc *linkEntry, root string, link bool) *subtreeSync {
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return &subtreeSync{c, loc, root, []string{root}, link, 0}
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}
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func (ts *subtreeSync) done() bool {
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return len(ts.missing) == 0
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}
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func (ts *subtreeSync) resolveAll(dest map[string]entry) error {
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for !ts.done() {
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hash := ts.missing[0]
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ctx, cancel := context.WithTimeout(context.Background(), ts.c.cfg.Timeout)
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e, err := ts.resolveNext(ctx, hash)
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cancel()
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if err != nil {
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return err
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}
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dest[hash] = e
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ts.missing = ts.missing[1:]
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}
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return nil
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}
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func (ts *subtreeSync) resolveNext(ctx context.Context, hash string) (entry, error) {
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e, err := ts.c.resolveEntry(ctx, ts.loc.domain, hash)
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if err != nil {
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return nil, err
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}
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switch e := e.(type) {
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case *enrEntry:
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if ts.link {
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return nil, errENRInLinkTree
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}
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ts.leaves++
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case *linkEntry:
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if !ts.link {
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return nil, errLinkInENRTree
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}
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ts.leaves++
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case *branchEntry:
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ts.missing = append(ts.missing, e.children...)
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}
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return e, nil
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}
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// linkCache tracks links between trees.
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type linkCache struct {
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backrefs map[string]map[string]struct{}
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changed bool
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}
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func (lc *linkCache) isReferenced(r string) bool {
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return len(lc.backrefs[r]) != 0
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}
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func (lc *linkCache) addLink(from, to string) {
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if _, ok := lc.backrefs[to][from]; ok {
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return
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}
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if lc.backrefs == nil {
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lc.backrefs = make(map[string]map[string]struct{})
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}
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if _, ok := lc.backrefs[to]; !ok {
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lc.backrefs[to] = make(map[string]struct{})
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}
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lc.backrefs[to][from] = struct{}{}
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lc.changed = true
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}
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// resetLinks clears all links of the given tree.
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func (lc *linkCache) resetLinks(from string, keep map[string]struct{}) {
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stk := []string{from}
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for len(stk) > 0 {
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item := stk[len(stk)-1]
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stk = stk[:len(stk)-1]
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for r, refs := range lc.backrefs {
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if _, ok := keep[r]; ok {
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continue
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}
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if _, ok := refs[item]; !ok {
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continue
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}
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lc.changed = true
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delete(refs, item)
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if len(refs) == 0 {
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delete(lc.backrefs, r)
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stk = append(stk, r)
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}
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}
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}
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}
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